Description
Given four integer arrays nums1
, nums2
, nums3
, and nums4
all of length n
, return the number of tuples (i, j, k, l)
such that:
0 <= i, j, k, l < n
nums1[i] + nums2[j] + nums3[k] + nums4[l] == 0
Solution
# use a dict to store the elements in nums1 and nums2 and their sum
hashmap = dict()
for n1 in nums1:
for n2 in nums2:
if n1 + n2 in hashmap:
hashmap[n1+n2] += 1
else:
hashmap[n1+n2] = 1
# if the -(a+b) exists in nums3 and nums4, we shall add the count
count = 0
for n3 in nums3:
for n4 in nums4:
key = - n3 - n4
if key in hashmap:
count += hashmap[key]
return count